[tex] \binom{6}{ \ \sqrt{6 + 3} } [/tex]
rasional kan lah bentuk akar tersebut...
[tex] \frac{6}{ \sqrt{6} + 3 } \\ = \frac{6}{ \sqrt{6} + 3} \times \frac{ \sqrt{6} - 3 }{ \sqrt{6} - 3 } \\ = \frac{6( \sqrt{6} - 3) }{( \sqrt{6} ) {}^{2} - {3}^{2} } \\ = \frac{6 \sqrt{6} - 18}{6 - 9} \\ = - \frac{6 \sqrt{6} - 18}{3} \\ = - \frac{3(2 \sqrt{6} - 6)}{3} \\ = 6 - 2\sqrt{6} [/tex]
[answer.2.content]
